Binary to ASCII in Python

Question

I'm trying to decode binary which are located in a .txt file, but I'm stuck. I don't see any possibilities this can go around.

def code(): testestest
  ascii = {'01000001':'A', ...}
  binary = {'A':'01000001', ...}
  print (ascii, binary)

  def encode():
    pass

  def decode(code,n):
    f = open(code, mode='rb') # Open a file with filename <code>
    while True:
      chunk = f.read(n)           # Read n characters at time from an open file
      if chunk == '':             # This is one way to check for the End Of File in Python 
        break
      if chunk != '\n':
        # Process it????
        pass

How can I take the binary in the .txt file and output it as ASCII?

Oh, yeah :-) I'm sorry. Is there any easy way the binary from the .txt file be outputted to ASCII? — Musa
– Musa, Commented Jan 28, 2016 at 14:11
What's your input? What's the expected output? This sound more easy than you're making it look. — tglaria
– tglaria, Commented Jan 28, 2016 at 14:13
Your answer is here. Just modify it according to your need. — jblixr
– jblixr, Commented Jan 28, 2016 at 14:15
can't you use int("01000001', 2) to convert into integer and then chr(65) to get char ? — furas
– furas, Commented Jan 28, 2016 at 14:16
You can convert between binary, ascii, and strings using bin, int, and chr. — Open AI - Opting Out
– Open AI - Opting Out, Commented Jan 28, 2016 at 14:16

tglaria · Accepted Answer · 2016-01-28 16:03:56Z

6

From your example, your input looks like a string of a binary formatted number.

If so, you don't need a dictionnary for that:

def byte_to_char(input):
     return chr(int(input, base=2))

Using the data you gave in the comments, you have to split your binary string into bytes.

input ='01010100011010000110100101110011001000000110100101110011001000000110101001110101011100110111010000100000011000010010000001110100011001010111001101110100001000000011000100110000001110100011000100110000'
length = 8
input_l = [input[i:i+length] for i in range(0,len(input),length)]

And then, per byte, you convert it into a char:

input_c = [chr(int(c,base=2)) for c in input_l]
print ''.join(input_c)

Putting it all together:

def string_decode(input, length=8):
    input_l = [input[i:i+length] for i in range(0,len(input),length)]
    return ''.join([chr(int(c,base=2)) for c in input_l])

decode(input)
>'This is just a test 10:10'

edited Jan 28, 2016 at 16:03

answered Jan 28, 2016 at 14:17

tglaria

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13 Comments

Musa Over a year ago

Thanks, but I think there need to be a dictionary for holding the mapping between binary string and ascii chars? This is the binary: 01010100011010000110100101110011001000000110100101110011001000000110101001110101011100110111010000100000011000010010000001110100011001010111001101110100001000000011000100110000001110100011000100110000

tglaria Over a year ago

Is that a question? No, you don't need it. you convert your binary string into an integer and then convert that integer into ascii.

Musa Over a year ago

Thanks, but the binary string is in an external file in a folder as mentioned.

tglaria Over a year ago

So? just load that string.

Musa Over a year ago

So in it will be... def code(): bin = int('0b110100001100101011011000110110001101111', 2) pass

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