I can't find an answer to this problem, other than people asking to use an array instead. That's not what I want. I want to declare a number of variables inside a for loop with the same name except for an index number.
I=0
For int in $ints;
Do i=[$i +1]; INTF$i=$int; done
It doesn't really work. When I run the script it thinks the middle part INTF$i=$int is a command.
Without an array, you need to use the declare command:
i=0
for int in $ints; do
i=$((i +1))
declare "intf$i=$int"
done
With an array:
intf=()
for int in $ints; do
intf+=( $int )
done
Bash doesn't handle dynamic variable names nicely, but you can use an array to keep variables and results.
[/tmp]$ cat thi.sh
#!/bin/bash
ints=(data0 data1 data2)
i=0
INTF=()
for int in $ints
do
((i++))
INTF[$i]=$int
echo "set $INTF$i INTF[$i] to $int"
done
[/tmp]$ bash thi.sh
set 1 INTF[1] to data0
I can't find a answer to this problem, other than people asking to use an array instead.That's because you should use an array instead.