creating a tuple using loop, rather than specifying each element separately

Question

I am trying to create a tuple as:

tuples = (i+1,
          db.entries[i].get("ENTRYTYPE"),
          db.entries[i].get("ID"),
          db.entries[i].get("title"),
          db.entries[i].get("author"),
          db.entries[i].get("journal"),
          db.entries[i].get("year")
          )

where db is a database, i is properly defined.

Now, the get("text") has ~40 different text. I can do it manually, and it is working. But is it possible to do it in some other way, e.g. loop like:

Entries = ["ENTRYTYPE", "ID", "title", "author" ...]
for entry in entries:
  tuples = (i+1, db.entries.get(entry)

Actually, I will get some values empty. And I need to keep the order. — BaRud
– BaRud, Commented Jan 26, 2016 at 19:31
What? Please update your question with more information and some test data. — pzp
– pzp, Commented Jan 26, 2016 at 19:35
You can't have empty places in tuple. You have to put None or something other in empty places. And you can do the same with list. — furas
– furas, Commented Jan 26, 2016 at 19:38

Chad S. · Accepted Answer · 2016-01-26 19:33:46Z

2

Should be as simple as tuples = (i+1,) + tuple(db.entries.get(e) for e in Entries)

answered Jan 26, 2016 at 19:33

Chad S.

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pzp · Accepted Answer · 2016-01-26 19:31:35Z

1

If you really need a tuple, try this:

tuples = tuple([i+1] + [db.entries.get(entry) for entry in entries])

answered Jan 26, 2016 at 19:31

pzp

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