Java: generic type array as function parameter

Question

I have some Java 8 code like the following snippet.

public class Test {
  static protected <T extends Comparable<T>> T[] myFunction(T[] arr) {
    // do stuff...
    return arr;
  }

  public static void main(String[] args) {
    int[] a = new int[] {1,4,25,2,5,16};
    System.out.println(Arrays.toString(myFunction(a)));
  }
}

When I try to run it, I get the error below:

Exception in thread "main" java.lang.Error: Unresolved compilation problem:
The method myFunction(T[]) in the type LottoResult is not applicable for the arguments (int[])

Why does this happen and how do I have to rewrite it to be able to also pass int[] arrays to myFunction?

int[] is primitive and T[] expects non-primitive types

Aksiom
– Aksiom

2016-01-11 13:34:11 +00:00
Commented Jan 11, 2016 at 13:34 — Aksiom
– Aksiom, Commented Jan 11, 2016 at 13:34

Konstantin Yovkov · Accepted Answer · 2016-01-11 13:33:18Z

9

An array T[] implies that the array is of some-reference type T, while you're passing an array of primitives (int[]). This is why you get the compilation error.

In order to get it working, you need to do:

Integer[] a = new Integer[] {1,4,25,2,5,16};

This will create an array of a reference type (Integer[]), because auto-boxing would have taken place.

answered Jan 11, 2016 at 13:33

Konstantin Yovkov

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