I am trying find out the matching element of an array for a given string.
var array = ["CODE1", "CODE2", "CODE3", "CODE4", "CODE5", "CODE6"];
var text = "alsdjklfjaaCODE2ladkslfj";
var resultCode;
for (var i in array) {
if (text.indexOf(array[i]) > -1) {
resultCode = array[i];
}
}
console.log(resultCode);
But I felt that it is not efficient way to iterate through array as that array was little big. Is there any alternative algorithm for my problem.
As of ES6, you can use Array.prototype.find and Array.prototype.includes
var array = ["CODE1", "CODE2", "CODE3", "CODE4", "CODE5", "CODE6"],
text = "alsdjklfjaaCODE2ladkslfj";
var resultCode = array.find(a => text.includes(a));
document.write(resultCode);
array.find(a => text.includes(a));
You can use Array.prototype.some()
The
some()method tests whether some element in the array passes the test implemented by the provided function.
if you expect only one match in the string. The iteration stops if the callback returns true.
var array = ["CODE1", "CODE2", "CODE3", "CODE4", "CODE5", "CODE6"],
text = "alsdjklfjaaCODE2ladkslfj",
resultCode;
array.some(function (a) {
if (~text.indexOf(a)) {
resultCode = a;
return true;
}
});
document.write(resultCode);
