Mapping an array in PHP with this array

Question

I have array as follows,

$arr['fixed_key'][0]['key1']['key2'] = 'y';
$arr['fixed_key'][1]['key1']['key2'] = 'y';
$arr['fixed_key'][2]['key1']['key2'] = 'n';
$arr['fixed_key'][3]['key1']['key2'] = 'n';

I want to remove all arrays which have key2='n', I can traverse through array in a loop and achieve this, as follows:

$l=length($arr);
for($i=0;$i<$l;$i++) {

    if($arr['fixed_key'][$i]['key1']['key2'] == 'n') {

        unset($arr['fixed_key'][$i]['key1']['key2']);

    }

}

My question is, is it possible to do this in better way, like array_map or array_walk, what is the best possible way?

you will do it with array_map and array_walk but you want to unset it in that functions also — jilesh
– jilesh, Commented Jan 7, 2016 at 5:21

Ninju · Accepted Answer · 2016-01-07 05:34:14Z

3

You can use array_filter

$arr['fixed_key'][0]['key1']['key2'] = 'y';
$arr['fixed_key'][1]['key1']['key2'] = 'y';
$arr['fixed_key'][2]['key1']['key2'] = 'n';
$arr['fixed_key'][3]['key1']['key2'] = 'n';

$filtered = array_filter($arr['fixed_key'], function ($val) { return $val['key1']['key2']  !== "n"; });

answered Jan 7, 2016 at 5:34

Ninju

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Comments

Vijayakumar S · Accepted Answer · 2016-01-07 05:31:20Z

1

We can achive by using array_search() and unset, try the following:

if(($key = array_search($del_value, $arr)) !== false) {
        unset($arr[$key]);
 }

answered Jan 7, 2016 at 5:31

Vijayakumar S

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2 Comments

Narendrasingh Sisodia Over a year ago

Nope you can't this'll work single dimensional array and not for multidimensional array

user1735921 Over a year ago

@Uchiha You are right, besides that, we also don't wanna traverse in the inner dimensions unnecessarily. Nimshad Abdul's solution looks good. We can't use unset($arr) inside arrap_map function, so array_filter is the best choice to go to.

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