storing output from piped cmd into string (bash) [duplicate]

Question

I am trying to put the output of a bash command (filename) into a string for later access.

echo "$(ls -Art | tail -n 1)"

successfully prints out the latest file updated in the directory (good).

The problem occurs when I try to store this into a var. to access later in the script.

Any suggestions on how to do so? I've seen different methods, but it didn't seem to work/ apply because I'm using the param -Art for ls.

Thanks!

further info: filename still gets kicked back as the {actual filename}: command not found

filename = `ls -Art | tail -n 1`

I assume you want something like this, in which case I don't see the problem unless you're using assignment incorrectly: $ x=$(ls -Art | tail -n 1) $ echo $x — Shane C
– Shane C, Commented Jan 1, 2016 at 22:19
shellcheck says "Don't put spaces around the = in assignments." — that other guy
– that other guy, Commented Jan 1, 2016 at 22:26

T. McT · Accepted Answer · 2016-01-01 22:29:54Z

0

shellcheck says "Don't put spaces around the = in assignments." – that other guy 1 min ago

@that-other-guy was correct. It had to do with the spaces around the '='

Thanks!

answered Jan 1, 2016 at 22:29

T. McT

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