Python 3.x - Separating Long Binary String to Short

Question

I had a question about dividing long binary string to shorter ones.

For example, I am trying to convert...

000000100000000011000000100000000010000000100000000001

to...

000000100000000011
000000100000000010
000000100000000001

So basically, I am looking for a python command so that the program can create new line every 18 digits and if possible, introduce a space between first 7 digits and last 11 digits. And then reverse them all back to longer string.

Blair · Accepted Answer · 2015-11-30 21:35:25Z

5

This will divide your long string into shorter strings.

>>> s = '000000100000000011000000100000000010000000100000000001'
>>> print('\n'.join([s[i:i + 7] + ' ' + s[i + 7:i + 18] for i in range(0,len(s),18)]))
0000001 00000000011
0000001 00000000010
0000001 00000000001

This will also put in the spaces you mentioned.

To go in the opposite direction, we can do the following:

>>> f = '0000001 00000000011\n0000001 00000000010\n0000001 00000000001'
>>> print(''.join([c for c in f if c in '01']))
000000100000000011000000100000000010000000100000000001

edited Nov 30, 2015 at 21:35

answered Nov 30, 2015 at 20:26

Blair

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6 Comments

Jason M Over a year ago

Thank you very much! Is there a commend to reverse them back together to "s" once thy have been splitted?

Dorian Dore Over a year ago

Why would you want to do that?

Jason M Over a year ago

Basically, I am editing binary value to change item number in game. The game uses hex values in the save file. So if I want to convert binary number to hex, I thought I need the long binary string again.

Blair Over a year ago

Edited to add the reverse operation. If this helped you, click the check mark button to mark this as accepted so others know it helped you too.

Reti43 Over a year ago

For the replacement f.replace('\n', '').replace(' ', '') is faster, even though the difference would be imperceptible for such small strings.

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Dorian Dore · Accepted Answer · 2015-11-30 20:24:17Z

1

val = '000000100000000011000000100000000010000000100000000001'
short_val = ''
for i range(len(val) - 1):
    if i % 16 == 0:
       print(short_val)
       short_val = ''
    else:
       short_val += val[i]

answered Nov 30, 2015 at 20:24

Dorian Dore

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