how to sort tuple value from list in python

Question

I have list of tuple values. I need to sort value by id from the tuple list. Can anyone help me to do this.

  l = [('abc','23'),('ghi','11'),('sugan','12'),('shankar','10')]

I need a output like this.

  l = [('shankar','10'),('ghi','11'),('sugan','12'),('abc','23')]

and also if i need to sort like this means

  l =  [('abc', '23'),('sugan', '12'),('ghi', '11'),('shankar', '10')]

There is a similar answer here (like Avinash Raj gave it): https://stackoverflow.com/questions/3121979/how-to-sort-list-tuple-of-lists-tuples — rocksteady
– rocksteady, Commented Nov 16, 2015 at 8:48

Avinash Raj · Accepted Answer · 2015-11-16 07:49:08Z

6

You may pass key param to sorted function.

>>> l = [('abc','23'),('ghi','11'),('sugan','12'),('shankar','10')]
>>> sorted(l, key=lambda x: int(x[1]))
[('shankar', '10'), ('ghi', '11'), ('sugan', '12'), ('abc', '23')]
>>>

answered Nov 16, 2015 at 7:49

Avinash Raj

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2 Comments

Python Team Over a year ago

if i need to sort like this means [('abc', '23'),('sugan', '12'),('ghi', '11'),('shankar', '10')]

Nhor Over a year ago

if you want it in descending order just use sorted(l, key=lambda x: int(x[1]), reverse=True)

Mangu Singh Rajpurohit · Accepted Answer · 2015-11-16 07:56:33Z

0

Try this to sort

sorted(yourList, key=lambda tupVal: float(tupVal[1]))

answered Nov 16, 2015 at 7:56

Mangu Singh Rajpurohit

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