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This is a common question I know, but this question is not regarding a standard encryption algorithm.

I am, as a "fun" venture, attempting to figure out how a text string is encrypted/transformed.

For example,

The string "aaa" (without quotes) becomes "516E12" (without quotes) and "bbb" (again without quotes) become "52BF3C".

Now I know that the new string is Hex so I have split the chars into groups:

51  6E  12

I also know that the first char in the string is the ASCII value for the char in hex minus 10.

a = 61
61 - 10 = 51

But then I get stumped on how the remaining chars are converted/transformed.

I don't necessarily want the answer given to me, but if someone could point me in a direction I would be very grateful.

EDIT: I was asked for more information, unfortunatly, all i have is the ability to input a string and get the result.

So i input "aaa" and got the above string and also the following results. input - output:

  • "bbb" is "52BF3C"
  • "ccc" is "53CFBC"
  • "abc" is "516DC6"

As you see, the first char is always the ASCII HEX value minus 10.

You ask for more info, but do not provide the info you would need.

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  • With so little information it is impossible to answer. Commented Oct 8, 2015 at 16:01
  • what kind of data do you have? Commented Oct 8, 2015 at 16:02
  • 2
    With this limited information, there are an infinite number of possible transformation algorithms. Commented Oct 8, 2015 at 16:02
  • a glance at this page: en.wikipedia.org/wiki/Rainbow_table will show your problem as stated is impossible to solve. Commented Oct 8, 2015 at 16:06
  • 1
    Would be interesting to see aaa vs aab vs aba Commented Oct 8, 2015 at 17:09

1 Answer 1

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Well, you'll require a bit more information than just a value and the encrypted value (btw.: where's the key). In general you'll have to decompile and analyze the code. Or atleast that's the usual way of doing this task. Good luck with just this little info. Encryption-algorithms are designed for one purpose: to prevent conclusions from the encrypted string to the value and vice versa without using the exact algorithm, so it's technically impossible to apply reverse engineering to this little information.

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