Reading an HTML File from Folder in Python

Question

I want to read an HTML file in Python 3.4.3.

I have tried:

import urllib.request
fname = r"C:\Python34\html.htm"
HtmlFile = open(fname,'w')
print (HtmlFile)

This prints:

<_io.TextIOWrapper name='C:\\Python34\\html.htm' mode='w' encoding='cp1252'>

I want to get the HTML source so that I can parse it with beautiful soup.

If you want to read you shouldn't open it for writing ;) open(fname, 'w') => open(fname, 'r'). — m02ph3u5
– m02ph3u5, Commented Sep 13, 2015 at 7:58

BLACKMAMBA · Accepted Answer · 2015-09-13 08:09:39Z

14

You will have to read the contents of the file.

HtmlFile = open(fname, 'r', encoding='utf-8')
source_code = HtmlFile.read()

edited Sep 13, 2015 at 8:09

BLACKMAMBA

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answered Sep 13, 2015 at 7:58

Vikas Ojha

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3 Comments

BLACKMAMBA Over a year ago

im getting this error for the above lineFile "C:/Python34/pretty.py", line 4, in <module> source_code = HtmlFile.read() File "C:\Python34\lib\encodings\cp1252.py", line 23, in decode return codecs.charmap_decode(input,self.errors,decoding_table)[0] UnicodeDecodeError: 'charmap' codec can't decode byte 0x81 in position 4411: character maps to <undefined>

Vikas Ojha Over a year ago

Use encoding to read the file - HtmlFile = open(fname, 'r', encoding='utf-8')

dKen Over a year ago

Remember to close the file when you're done: HtmlFile.close()

Yogesh Awdhut Gadade · Accepted Answer · 2019-05-29 08:38:57Z

1

I was trying to read the saved HTML file in the folder. I tried code mentioned by Vikasa but was getting an error. So I changed the code and tried to read it again it worked for me. The code is as follows:

    fname = 'page_source.html' #this html file is stored on the same folder of the code file
    html_file = open(fname, 'r')
    source_code = html_file.read()

print the html page using

source_code

It will print the content read from the page_source.html file.

answered May 29, 2019 at 8:38

Yogesh Awdhut Gadade

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