scala list java.lang.String

Question

So this is my code:

import scala.collection.mutable.MutableList 

val list = MutableList[Any]()
val input = scala.io.StdIn.readLine("Please enter your list of values separated by a comma:").split(",")
val toList = for (e <- input if(!e.trim.isEmpty())) yield e.trim.toString
list += toList
println(list)

But when the "list" gets printed it doesn't show me the input seperated by commas, besides it prints the following:

MutableList([Ljava.lang.String;@d716361)

Why is that so?

ka4eli · Accepted Answer · 2015-08-29 14:17:05Z

3

Now your input is an Array which doesn't have pretty toString representation. Change your input to:

val input = scala.io.StdIn.readLine("Please enter your list of values separated by a comma:").split(",").toList

answered Aug 29, 2015 at 14:17

ka4eli

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3 Comments

bajro Over a year ago

Ah okay. So if I use the .split(",") operator it is putting my input into an array of Strings splitted by a comma? and therefore its not only one string but an array containing strings?

ka4eli Over a year ago

@ArmaGeddon, exactly!

bajro Over a year ago

ah okay thats explains a lot...But i thought that too because it was always telling me that it has found an Array(String) :)

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