How to delete elements of and array by two attributes in AngularJS?

Question

I have an array of objects in AngularJS like this:

var example = [ {id:'1',
                 read: false,
                 folder: 'inbox'},
                {id:'2',
                 read: true,
                 folder: 'inbox'},
                {id:'3',
                 read: true,
                 folder: 'trash'},
                 {id:'4',
                 read: false,
                 folder: 'trash'}];

And I need to delete any object that has the attributes folder == 'trash' and read == true at the same time.

So I tried to do it like this with lodash:

example = lodash.filter(example, function(value, index) {
    return (value.folder !== 'trash') && (value.read !== true);
});

It should delete only the item #3, but it deletes #3 and #4.

Obviously I'm not understanding how lodash.filter really works.

Can someone please help?

Satpal · Accepted Answer · 2015-08-24 18:39:59Z

1

You logical operator is not correct. set the condition to folder == 'trash' and read == true and the negate it.

example = lodash.filter(example, function(value) {
    return (value.folder == 'trash' && value.read == true) == false;
});

answered Aug 24, 2015 at 18:39

Satpal

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Comments

rob · Accepted Answer · 2015-08-24 18:41:54Z

0

You need to remove the quotes around 'true'. You want to keep all the elements where the folder is not 'trash' or the read property is not true so your logic would look like this

return (value.folder !== 'trash') || (value.read !== true);

answered Aug 24, 2015 at 18:41

rob

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Comments

pguetschow · Accepted Answer · 2015-08-24 18:42:25Z

0

The operator !== is false. use == instead.

  return (value.folder == 'trash' && value.read == 'true') == false;

answered Aug 24, 2015 at 18:42

pguetschow

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