golang exception to rule "interface pointer can't implement interface"

Question

In golang.org's official FAQ, under pointers there is this quote: "The insight is that although a pointer to a concrete type can satisfy an interface, with one exception a pointer to an interface can never satisfy an interface"

Out of curiosity, what is that exception to the above rule? i.e when can an interface pointer implement an interface?

LanceH · Accepted Answer · 2015-07-29 18:10:24Z

1

Just below it says:

The one exception is that any value, even a pointer to an interface, can be assigned to a variable of empty interface type (interface{}). Even so, it's almost certainly a mistake if the value is a pointer to an interface; the result can be confusing.

answered Jul 29, 2015 at 18:10

LanceH

1,75713 silver badges23 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Javier Zunzunegui Over a year ago

You are right, I just tested it and it runs OK. Thanks func main() { type I interface{} f := func(p interface{}) { fmt.Println("runs") } var i I = 1 f(&i) }

Collectives™ on Stack Overflow

golang exception to rule "interface pointer can't implement interface"

1 Answer 1

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related