Using an if statement in JS with custom parameter

Question

I'm trying to make it so that when someone types !familyfortunes %NAME% in message that it will run with the command and take the parameter (%NAME%) from the message and then store it in a variable.

I thought I could use if(message.toLowerCase.indexOf("!familyfortunes") !=-1){} and store $message into another variable but split to remove !familyfortunes so it only kept the username but that keeps returning the error:

greatbritishbg: !familyfortunes lol [10:53:39] error - TypeError: undefined is not a function at null. (example.js:68:29)

Which is the .split() part.

client.addListener('chat', function (channel, user, message) {
    console.log(user.username + ': ' + message);
    if (message.toLowerCase() === '!familyfortunes') { //If message contains !familyfortunes
        //var res = messageString.split("familyfortunes ");// Remove Family Fortunes to just get username
        client.say(channel, 'Latest Follower: ' + Follower.response);
        var raidName = Follower.response;
        io.emit('follow', raidName);
    }
}

Any advice on how I can tackle this would be appreciated. Thanks.

msfoster · Accepted Answer · 2015-06-10 10:22:04Z

1

You are very close. Note that toLowerCase is a function, so you'll need to do message.toLowerCase().indexOf(). I dont know if the message must start with the command or not, but I assume that it has to. Quick example:

var msg = "!familyfortunes param1 param2";
if (msg.toLowerCase().indexOf("!familyfortunes") == 0) {
    var parts = msg.split(" ");
    if(parts.length > 1) {
        parts.shift();
        console.log(parts.join(" "));
    }
}

var parts = msg.split(" ") splits the string on space and return an array. msg.shift() removes the first entry in the array(!familyfortunes), and then msg.join(" ") take the remaining parts of the array and build a string, separated by a space.

If you only allow one value after the keyword, you can check for parts.lenght == 2 and just do console.log(parts[1]) to get the parameter.

edited Jun 10, 2015 at 10:22

answered Jun 10, 2015 at 10:12

msfoster

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1 Comment

Bradly Spicer Over a year ago

hey @msfoster thanks for that, been looking at documentation and wondering for a while. With regards to the param1 and param2 I assume it uses the spaces to differentiate the different parameters? (Just trying to fully understand before I go ahead and use it)

carlo-colombo · Accepted Answer · 2015-06-10 10:17:26Z

1

You should try with a regexp

var r =/!familyfortunes\s+(.*)/i
var message = "!familyfortunes %NAME%"
message.match(r)
>> ["!familyfortunes %NAME%", "%NAME%"]

the regex match a string starting with !familyfortunes, one or ore spaces and then the argument of the command. The first group is the argument of the command.

answered Jun 10, 2015 at 10:17

carlo-colombo

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