Get current URL from browser using python

Question

I am running an HTTP server which serves a bitmap according to the dimensions in the browser URL i.e localhost://image_x120_y30.bmp. My server is running in infinite loop and I want to get the URL any time user requests for BITMAP, and at the end I can extract the image dimensions from the URL.

The question asked here:

How to get current URL in python web page?

does not address my problem as I am running in infinite loop and I want to keep on getting the current URL so I can deliver the requested BITMAP to the user.

possible duplicate of How to get current URL in python web page? — Liam Giannini
– Liam Giannini, Commented May 27, 2015 at 10:07

Andersson · Accepted Answer · 2015-05-27 10:16:01Z

14

If to use Selenium for web navigation:

from selenium import webdriver
driver = webdriver.Firefox()
print (driver.current_url)

answered May 27, 2015 at 10:16

Andersson

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6 Comments

StealthTrails Over a year ago

I am running python 2.7 and I got following error ImportError: No module named selenium @Andersson

Andersson Over a year ago

Selenium compatible with 2.7 as well as with 3.4. You need to install this package first and then import it within code. Try pip install selenium

StealthTrails Over a year ago

it is now working but it opens a new browser window of firefox , what I want is to get the url from browser.

Andersson Over a year ago

You can access page of required site with driver.get('put_your_site_name') and then get page url with driver.current_url after each loop iteration P.S. Please put more info about how your script works/should work or just show the part of existed code

bhattraideb Over a year ago

I'm using chrome and I a getting data:, with self.driver.current_url

|

Tasneem Haider · Accepted Answer · 2016-03-11 13:35:24Z

3

You can get the current url by doing path_info = request.META.get('PATH_INFO') http_host = request.META.get('HTTP_HOST'). You can add these two to get complete url. Basically request.META returns you a dictionary which contain a lot of information. You can try it.

answered Mar 11, 2016 at 13:35

Tasneem Haider

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Comments

Heather Claxton · Accepted Answer · 2019-05-10 20:06:38Z

1

I just solved a class problem similar to this. We've been using Splinter to walk through pages (you will need to download splinter and Selenium). As I walk through pages, I periodically need to pull the url of the page I'm currently on. I do that using the command new_url = browser.url Below is an example of my code.

I do this using the following code.

##import dependencies
from splinter import browser
import requests


## go to original page 
browser.visit(url)

## Loop through the page associated with each headline
for headline in titles:
    print(headline.text)
    browser.click_link_by_partial_text(headline.text)
## Now that I'm on the new page, I need to grab the url
    new_url = browser.url
    print(new_url)
## Go back to original page
    browser.visit(url)

edited May 10, 2019 at 20:06

answered May 10, 2019 at 20:00

Heather Claxton

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Comments

SuperNova · Accepted Answer · 2020-01-22 06:44:30Z

0

Below is the solution I use in Django.

For eg.,. if browser url is https://www.example.com/dashboard

try:
    from urlparse import urlparse
except ImportError:
    from urllib.parse import urlparse

frontend_url = request.META.get('HTTP_REFERER')
url = urlparse(frontend_url)
print (url)
# ParseResult(scheme='https', netloc='example.com', path='/dashboard', params='', query='', fragment='')

answered Jan 22, 2020 at 6:44

SuperNova

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Comments

Akash Patel · Accepted Answer · 2023-06-14 09:10:51Z

0

    Hello you can use below code in order to achieve URL from open browser
    
    import os
    import webbrowser
    import pyperclip
    import time
    import keyboard
    import pygetwindow as gw
    import pyautogui
    
    @app.route("/")
    def redirect_to_authorization():
        redirect_url = f"https://www.google.com"
        webbrowser.open(redirect_url)
        time.sleep(5)
        browser_window = gw.getActiveWindow()
        browser_window.activate()
        pyautogui.hotkey('ctrl', 'l')
        time.sleep(2)
        pyautogui.hotkey('ctrl', 'c')
        keyboard.press_and_release('ctrl + c')
        time.sleep(0.5) 
        url = pyperclip.paste()
        print(url)
        # os.system("taskkill /f /im chrome.exe")
        index = url.find('code=')
        if index != -1:
            code = url[index + len('code='):]
            print("Code:", code)
        # os.system("taskkill /f /im chrome.exe")
        return {"Token" : code}

# Or you can use below code too

    @app.route("/CodeTwo")
    def redirect_to_authorization():
        redirect_url = f"https://www.google.com"
        webbrowser.open(redirect_url)
        time.sleep(5)
        active_window = gw.getActiveWindow()
        if active_window is not None:
            title = active_window.title
            if " - Google Chrome" in title:
                # Extract the URL from the title
                url = title.split(" - Google Chrome")[0]
                return {"Token" : url}

answered Jun 14, 2023 at 9:10

Akash Patel

1

1 Comment

Community Over a year ago

As it’s currently written, your answer is unclear. Please edit to add additional details that will help others understand how this addresses the question asked. You can find more information on how to write good answers in the help center.

Sipher_ · Accepted Answer · 2018-06-10 15:26:50Z

-8

You could use the requests module:

import requests


link = "https://stackoverflow.com"
data = requests.request("GET", link)
url = data.url

edited Jun 10, 2018 at 15:26

answered Jan 5, 2018 at 5:28

Sipher_

699 bronze badges

1 Comment

Paulo Fabrício Over a year ago

This solution doesn't answer what he needs. It also has errors as you passed url instead of variable link as parameter to request.

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