Nested for loops with if/else in Javascript

Question

I just don't get it why when I use this,

for(in=1; in<=3;in++) {
    for(out=1; out<=2; out++) {
        console.log('*')
    }
}

it prints 6 stars which seems right to me, And when i use it with if/else like this,

for(in=0; in<=3; in++) {
    for(out=0; out<=2; out++) {
        if(in == 9) {
            console.log('inside');
        }
    }
    console.log('outside');
}

(outside) will be printed 4 times I really don't get it why is it like this ?

you have in=0; in<=3; in++ which will loop it 4 times... so ouside is printed 4 times.... — Arun P Johny
– Arun P Johny, Commented May 22, 2015 at 1:25
It's not in the if statement, so why shouldn't it be printed every time? — Barmar
– Barmar, Commented May 22, 2015 at 1:26
Thank you that makes it a little bit clear for me, but what happened now with out=0; out<=2; out++ ? — Hesham Abdalla
– Hesham Abdalla, Commented May 22, 2015 at 1:27

Paulo Mendes · Accepted Answer · 2015-05-22 01:25:50Z

5

console.log('outside') is inside the first loop which goes from 0 to 3, so it's printed four times. 'inside' is never printed because in never reaches 9

answered May 22, 2015 at 1:25

Paulo Mendes

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1 Comment

Paulo Mendes Over a year ago

Your if statement does nothing because in never reaches 9. Since there's nothing else inside the inner (out) loop, the loop is useless as well.

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