storing multiple checkboxes value in a variable or array

Question

so this works fine

HTML

<p></p>
<select id="single">
    <option>Single</option>
    <option>Single2</option>
</select> 
<select id="multiple" multiple="multiple">
    <option selected="selected">Multiple</option>
    <option>Multiple2</option>
    <option selected="selected">Multiple3</option>
</select>

<div>
    <span class="label">Hobbies</span>
    <input type="checkbox" name="hobby" id="hel" value="hel">
    <label for="hel">hel</label>
    <input type="checkbox" name="hobby" id="pickle" value="pickle">
    <label for="pickle">Pickle eating</label>
    <input type="checkbox" name="hobby" id="walnut" value="walnut">
    <label for="walnut">Making walnut butter</label>
</div>

function displayVals() {
var singleValues = $( "#single" ).val();
var multipleValues = $( "#multiple" ).val() || [];
$( "p" ).html( "<b>Single:</b> " + singleValues +
    " <b>Multiple:</b> " + multipleValues.join( ", " ) );}

$( "select" ).change( displayVals );
displayVals();

http://jsfiddle.net/bfha4881/

but when I change the JQuery Selector to input it returs multipleValues.join() is not a function!

function displayVals() {
var singleValues = $( "#single" ).val();
var multipleValues = $( "input[name='hobby']:checked" ).val() || [];
$( "p" ).html( "<b>Single:</b> " + singleValues +
    " <b>Multiple:</b> " + multipleValues.join( ", " ) );
}

$( "input" ).change( displayVals );
displayVals();

so what am I doing wrong?

Laurentiu Petrea · Accepted Answer · 2015-05-08 08:30:18Z

3

Try

var values = [];    
$( "input[name='hobby']:checked" ).each(function(){
    values.push($(this).val());
});
var str = values.join(", ");

Also, you can concatenate directly in the "each", but remember to remove the ", " from the last loop.

edited May 8, 2015 at 8:30

answered May 8, 2015 at 8:24

Laurentiu Petrea

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Comments

Arun P Johny · Accepted Answer · 2015-05-08 08:22:04Z

1

For input elements, the returned value will be string, so for array of checkboxes you can iterate over checked inputs and then use .map() to create an array as below

function displayVals() {
    var singleValues = $("#single").val();
    var multipleValues = $("#multiple").val() || [];
    var hobbies = $('input[name="hobby"]:checked').map(function () {
        return this.value;
    }).get();
    $("p").html("<b>Single:</b> " + singleValues +
        " <b>Multiple:</b> " + multipleValues.join(", ") +
        " <b>Hobies:</b> " + hobbies.join(", "));
}

$("select, input").change(displayVals);
displayVals();

Demo: Fiddle

answered May 8, 2015 at 8:22

Arun P Johny

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2 Comments

yokimoto Over a year ago

can you please explain the last part of this: var multipleValues = $("#multiple").val() || []; does the: .val()|| [] indicates single or multiple value?

Arun P Johny Over a year ago

@Sam-Gh. if the select element is a multi select then .val() will return an array of selected values.. but if no values is selected then null is returned so || [] used to return an empty array if there are no elements selected

Brane · Accepted Answer · 2015-05-08 08:47:59Z

0

You need to get all checkboxes, you can do that with .each() function...

var checkBoxes = "";
function displayVals() {
  var singleValues = $( "#single" ).val();
  $( "input[name='hobby']:checked" ).each(function() {
        checkBoxes += $(this).val() + " ";
    });

  $( "p" ).html( "<b>Single:</b> " + singleValues +
    " <b>Multiple:</b> " + checkBoxes );
    checkBoxes = "";
}

Here is working example: jsfiddle

answered May 8, 2015 at 8:47

Brane

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storing multiple checkboxes value in a variable or array

http://jsfiddle.net/bfha4881/

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