PHP array to json

Question

I must be doing something stupid here. I have this php file:

$arr = array("result" => "dasdasds;bks fjsdgjdklsds j&*", "text" =>"23 + 2   = &#160; ?");

echo json_encode($arr);

And I call it in my js file:

/*
   * PHP array to json
   */

  $("#jsonform").submit(function(e){

      $.ajax({
          url:"/phparraytojson/Helper.php", 
          success: function(data){ 
             console.log(data.result) //undefined
             console.log(data); //{"result":"dasdasds;bks fjsdgjdklsds j&*","text":"23 + 2 = &#160; ?"} 
          }

      })
      e.preventDefault();
  })

What exactly is your error? Don't you mind adding more information to your question? — Keep Coding
– Keep Coding, Commented Apr 18, 2015 at 7:31
Just a side notice, if you are going to output JSON on your server you should adjust the headers accordingly, place next line as first in your script : header('Content-type: application/json'); — DarkBee
– DarkBee, Commented Apr 18, 2015 at 8:23

dave1010 · Accepted Answer · 2015-04-18 07:32:31Z

1

Adding dataType: "json" should fix this:

$.ajax({
      url:"/phparraytojson/Helper.php", 
      dataType: "json",
      success: function(data){ 
         console.log(data.result) //undefined
         console.log(data); //{"result":"dasdasds;bks fjsdgjdklsds j&*","text":"23 + 2 = &#160; ?"} 
      }

  })

answered Apr 18, 2015 at 7:32

dave1010

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Comments

Shah Nawaz · Accepted Answer · 2015-04-18 07:36:24Z

1

you should be use datatype:'json' in ajax call
$.ajax({
    url:"/phparraytojson/Helper.php", 
    async: false,
    dataType: 'json',
    success: function(data){ 
       console.log(data.result) //undefined
       console.log(data); //{"result":"dasdasds;bks fjsdgjdklsds j&*","text":"23 + 2 = &#160; ?"
                   } 
     }

});

answered Apr 18, 2015 at 7:36

Shah Nawaz

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Comments

Shashikumar Misal · Accepted Answer · 2015-04-18 07:40:00Z

1

In ajax call you have to add format of output you are receiving from php. ie: dataType:"json"

$("#jsonform").submit(function(e){

  $.ajax({
      url:"/phparraytojson/Helper.php", 
      dataType:"json",              //Dont miss to add
      success: function(data){ 
         console.log(data.result) //undefined
         console.log(data); //{"result":"dasdasds;bks fjsdgjdklsds j&*","text":"23 + 2 = &#160; ?"} 
      }

  })
  e.preventDefault();  });

edited Apr 18, 2015 at 7:40

answered Apr 18, 2015 at 7:33

Shashikumar Misal

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