running a shell script from another script

Question

I have a script in unix that looks like this:

#!/bin/bash

gcc  -osign sign.c

./sign < /usr/share/dict/words | sort | squash > out

Whenever I try to run this script it gives me an error saying that squash is not a valid command. squash is a shell script stored in the same directory as this script and looks like this:

#!/bin/bash
awk -f squash.awk

I have execute permissions set correctly but for some reason it doesn't run. Is there something else I have to do to make it able to run like shown? I am rather new to scripting so any help would be greatly appreciated!

squash → ./squash

Biffen
– Biffen

2015-04-17 19:30:32 +00:00
Commented Apr 17, 2015 at 19:30 — Biffen
– Biffen, Commented Apr 17, 2015 at 19:30

dg99 · Accepted Answer · 2015-04-17 22:17:31Z

2

As mentioned in @Biffen's comment, unless . is in your $PATH variable, you need to specify ./squash for the same reason you need to specify ./sign.

When parsing a bare word on the command line, bash checks all the directories listed in $PATH to see if said word is an executable file living inside any of them. Unless . is in $PATH, bash won't find squash.

To avoid this problem, you can tell bash not to go looking for squash by giving bash the complete path to it, namely ./squash.

answered Apr 17, 2015 at 22:17

dg99

5,7383 gold badges40 silver badges51 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

running a shell script from another script

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related