JS Append Row in HTML Table

Question

I have a hidden field with some values, I have to append these values in HTML table.The number of columns in table is fixed. I have appended successfully,but after first row,it should append data in new row,instead it is appending in the same row. This is how I am doing

$("#btntbl").click(function () {
                debugger
                var tabl = $("#testTable");
                var vals = $("#txthidden").val();
                for (var i = 0; i < vals.split(";").length; i++) {                       
                        for (var j = 0; j < vals.split(";")[i].split(",").length; j++) {
                        tabl.append("<td>" + vals.split(";")[i].split(",")[j] + "</td>");
                    }
                }
            });

Also note that some users dont have value of disabled column JS Fiddle How can I add new row each time clicking the button?

dfsq · Accepted Answer · 2015-04-12 12:48:47Z

2

You need to split twice and create tr for each row:

$("#btntbl").click(function () {

  var tabl = $("#testTable"),
      vals = $("#txthidden").val(),
      rows = vals.split(';'),
      columns, i;

  for (i = 0; i < rows.length; i++) {
    columns = rows[i].split(',');
    tabl.append(
      '<tr>' + 
          '<td>' + columns[0] + '</td>' + 
          '<td>' + columns[1] + '</td>' + 
          '<td>' + (columns[2] || '') + '</td>' + 
      '</tr>'
    );
  }
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="button" id="btntbl" value="Export to table">
<input type="hidden" value="User1,pwd1;User2,pwd2,disabled;User3,pwd3,disabled;User4,pwd4" id="txthidden" />
<table id="testTable" border="2">
    <thead valign="top">
        <tr>
            <th>User</th>
            <th>Password</th>
            <th>Disabled</th>
        </tr>
    </thead>
</table>

answered Apr 12, 2015 at 12:48

dfsq

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2 Comments

Pratik Joshi Over a year ago

@ dsfq : Hi dont you think for templating ,we should use Angular js or Mustache , Handle bars instead of Speghetti jQuery code ?

dfsq Over a year ago

@jQuery.PHP.Magento.com For more complex applications for sure. But in this case I' don't know OP's set up, so I can't introduce one more dependency without real need. For this simple example I would go with string concatenation.

charlietfl · Accepted Answer · 2015-04-12 12:45:25Z

1

Just change target by adding a row

Change

var tabl = $("#testTable");

To

var tabl = $('<tr>');
$("#testTable").append( tab1);

answered Apr 12, 2015 at 12:45

charlietfl

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Comments

Exception · Accepted Answer · 2015-04-12 12:56:39Z

1

Here is how you can do it

var convertToTable = function (val) {
   val = val.split(';');
   val = val.map(function (v) {
      v = v.split(',');
      if (v.length === 2) v[v.length] = 'NA';
      return '<td>' + v.join('</td><td>') + '</td>';
   });
   val = '<tr>' + val.join('</tr><tr>') + '</tr>';
   return val;
}

and then

tabl.html(convertToTable(vals));

Demo here

answered Apr 12, 2015 at 12:56

Exception

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Comments

Roko C. Buljan · Accepted Answer · 2015-04-12 13:07:18Z

1

jsFiddle demo

$("#btntbl").click(function () {                  
    var parts = $("#txthidden").val().split(";"), i=0;
    for (;i<parts.length;) {
        var j=0, tr="<tr>", subParts=parts[i++].split(",");          
        for (;j<3;)  tr += "<td>" + (subParts[j++]||"") +"</td>"; // concatenate
        $("#testTable").append( tr +"</tr>" );                    // Append once
    }
});

edited Apr 12, 2015 at 13:07

answered Apr 12, 2015 at 12:46

Roko C. Buljan

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2 Comments

Syed Salman Raza Zaidi Over a year ago

its working but its appending User1, Pwd1 then User2,pwd2 in same row, I need User1,PWd1 in first row,then User2,Pwd2 in second row

Roko C. Buljan Over a year ago

@SyedSalmanRazaZaidi edited. (moved "<tr>" stuff inside the for loop)

Eugene Glova · Accepted Answer · 2015-04-12 12:52:00Z

0

You forgot about TD tag, just use open tag before TD and close it in the end

answered Apr 12, 2015 at 12:52

Eugene Glova

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