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I have two numpy arrays ym and r_div with shapes (110,) and (120,). I want to divide ym with r_div, i.e. the first element of ym gets divided by the first element of r_div, the second element by second element and so on. I tried converting both the arrays to lists and dividing them, but no avail. Tried a truediv and map, but not able to get the values in map.

This is what I tried so far:

from operator import truediv
norm_y = map(truediv, ym_list, first)

and converting them to lists, and dividing them, which resulted in a TypeError.

The arrays don't match in shapes, but I want to use only the first 110 elements of r_div.

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You can slice r_div to get the first 110 values before you divide:

ym / r_div[:110]

The / operator does division element-wise on NumPy arrays.

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4 Comments

"true division" usually refers to the non-floored version: i.e., the one that corresponds to / rather than // (in Python 3, at least).
Hi, thank you for your response @ajcr. I tried that. The resultant array is of shape (110, 110). I want it to be (110,). Basically, in // or /, every element in ym is getting divided by every element in r_div. the resultant array should have elements as first element = first of ym/first of r_div, second element = second of ym/second of r_div, and so on.
@magnus_prime: if your arrays ym and r_div are both one-dimensional, I don't see how the division will create a two-dimensional array - are you certain that both only have one dimension?
@ajcr : Sorry, got it! I made a typo while copying your code in the variable names! Thanks.

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