How to let a class variable in python refer to a static method of the same class?

Question

I have a class that has a class variable and a static method and I need to let the class variable contain a callback to the static method.

The class looks like:

class Test(object):
    ref = ???? #this should be my reference

    @staticmethod
    def testmethod(anyparam="bla"):
        print "it works"

How can I do this? Is this even possible?

I am using python 2

EDIT: The real example is this:

class reg(cmd): 

    bla = {
        'def': [ ... ],
        'rem': [ ...,
            PIPE.return_response(fail_callback=HERE_I_NEED_THE_REF),
            ...
        ]
    }

    @classmethod
    def testmethod(cls, aco):
        print "i want to see this on fail"

Hmm ok, but how can I reference it then in the "ref" variable? simply writing ref = Test.testmethod does not work — Simon Hessner
– Simon Hessner, Commented Mar 26, 2015 at 15:26
not possible because in my real use case "ref" is an dict containing lists and i only need to set one element in one list of one dict to the testmethod... — Simon Hessner
– Simon Hessner, Commented Mar 26, 2015 at 15:29
I don't understand then. Can you please provide input and expected output? — matino
– matino, Commented Mar 26, 2015 at 15:30
seems to be not possible because when the dict is defined the class is not completely built. so I cannot refer to those functions because they are not available yet... is this right? — Simon Hessner
– Simon Hessner, Commented Mar 26, 2015 at 15:39

tdelaney · Accepted Answer · 2015-03-26 15:56:09Z

1

You are right about the problems of referencing the static method during class creation. Test isn't in the namespace yet, and even if you define ref below testmethod, the static method definition magic isn't complete. You can, however, patch the class after its created:

class reg(cmd): 

    bla = {
        'def': [ ... ],
        'rem': [ ...,
            PIPE.return_response(fail_callback=HERE_I_NEED_THE_REF),
            ...
        ]
    }

    @classmethod
    def testmethod(cls, aco):
        print "i want to see this on fail"

Test.ref["rem"][??] = PIPE.return_response(fail_callback=Test.testmethod)

edited Mar 26, 2015 at 15:56

answered Mar 26, 2015 at 15:35

tdelaney

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Comments

Heisenberg · Accepted Answer · 2015-03-26 15:40:46Z

0

If I understand your question correctly, you can do this.

class Test(object):
    def __init__(self):
        self.ref = self.testmethod

    @staticmethod
    def testmethod(anyparam="bla"):
        print "it works"

answered Mar 26, 2015 at 15:40

Heisenberg

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martineau · Accepted Answer · 2015-03-26 15:52:49Z

0

Just define the class variable outside the class following the rest of its definition:

class reg(cmd):
    @classmethod
    def testmethod(cls, aco):
        print "i want to see this on fail"

reg.bla = {
        'def': [ '...' ],
        'rem': [ '...',
            PIPE.return_response(fail_callback=reg.testmethod),
            '...'
        ]
    }

answered Mar 26, 2015 at 15:52

martineau

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