How to convert integer to unsigned 32 bit in python?

Question

For example, if we take 1 and transform it to unsigned 32-bits, it will be 00000000000000000000000000000001

How could you achieve this in python?

Do you mean for display purposes, or do you need to convert a number into a type that is exactly 32 bits (for example., to pack it into a structure)? — GoBusto
– GoBusto, Commented Feb 13, 2015 at 8:35
What is the problem you are trying to solve? Please read about the X-Y problem. — Some programmer dude
– Some programmer dude, Commented Feb 13, 2015 at 8:36
The solution you want is the conversion, but it's not the actual problem you're trying to solve. The problem you're trying to solve may have other solutions. And by not telling us why you want this conversion it will make it harder to give you a solution that works in a satisfactory (for you) way. — Some programmer dude
– Some programmer dude, Commented Feb 13, 2015 at 8:42

Westly White · Accepted Answer · 2016-12-01 23:38:52Z

2

def convert(i):
    return int(bin(i+2**32)[-32:])

print convert(1)
print convert(32)
print convert(100)
print convert(-1)
print type(convert(1))

outputs

00000000000000000000000000000001
00000000000000000000000000100000
00000000000000000000000001100100
11111111111111111111111111111111
<type 'long'>

answered Dec 1, 2016 at 23:31

Westly White

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Comments

optimist · Accepted Answer · 2015-02-13 08:39:57Z

0

bin(1)[2:].zfill(32)

'00000000000000000000000000000001'

answered Feb 13, 2015 at 8:39

optimist

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This code creates a string representing 32 bits as "0" or "1"; it doesn't actually create a 32-bit integer value.