Getting variable name in Python?

Question

I have this method that takes in an unknown number of args and I have some variables from another class that I want to match the arg variable name to. The variable names are the same across this current class and the OtherClass. I was thinking something like:

def my_method(self, *args):
    for arg in args:
        OtherClass.arg_variable_name = arg # where "arg" on the right is the value

How could I do this effectively in python?

x=5;def n(p):print "varname is ?"; n(x) ; is the var name of 5 x or p ? multiple names can point to the same object... what is the actual variable name of the object? — Joran Beasley
– Joran Beasley, Commented Feb 11, 2015 at 18:34

Jaehyun Yeom · Accepted Answer · 2015-02-11 18:26:57Z

3

I think you should use **kwds instead of args. *args are values, so the caller can send it not with the variable, but just value itself.

my_object.my_method(1, 2, 3, "string")

If you use **kwds, you'll know the key, value pairs.

answered Feb 11, 2015 at 18:26

Jaehyun Yeom

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HavelTheGreat · Accepted Answer · 2015-02-11 18:39:09Z

1

You could use something like

dict( (name,eval(name)) for name in['self','args']

To get a dict with the values for each argument, and then from there you could match the dict values with your respective arg variable name.

edited Feb 11, 2015 at 18:39

answered Feb 11, 2015 at 18:28

HavelTheGreat

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