Bash Script Returning Value and Echo

Question

I'm following the code mentioned here but it doesn't echo $result. Here is my code, I added quotations around the "$result". The echo in myfunc works, but the echo outside the function doesn't work. What is the problem? How do I fix it?

My Code:

#!/bin/bash

function myfunc()
{
    local myresult="Hello World"

}

result=$(myfunc)   
echo "$result"

which function is it called from? Is this the only small script? — SMA
– SMA, Commented Jan 10, 2015 at 15:56
@almasshaikh - Yes, it's the complete script. I'm just copying the code that was in the link I posted. — user4350786
– user4350786, Commented Jan 10, 2015 at 15:57
@lurker - That is the link I posted. I got the code from there. — user4350786
– user4350786, Commented Jan 10, 2015 at 15:59
But it seems you mixed up their two examples. You were attempting to use half of one with half of the other. — lurker
– lurker, Commented Jan 10, 2015 at 16:00

Gilles Quénot · Accepted Answer · 2015-01-10 15:57:40Z

1

#!/bin/bash

function myfunc()
{
    local myresult="Hello World"
    echo "$myresult" # the function need to return something
}

result=$(myfunc)   
echo "$result"

answered Jan 10, 2015 at 15:57

Gilles Quénot

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4 Comments

user4350786 Over a year ago

Is the variable set in $result variable? Can I now use my $result

Jason Hu Over a year ago

@CharlesWhitfield `` and $() are the same, will capture standard output of inner command and set it to a variable.

Gilles Quénot Over a year ago

@CharlesWhitfield sure it does

user4350786 Over a year ago

Thanks - I thought the echo in the function wasn't needed. Guess I was wrong.

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