Is there any way how to code recursive function containing if with lamba? Is possible to rewrite this using lambda.
def factorial(x):
if x <= 1:
return 1
return x * factorial(x - 1)
print(factorial(5))
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Why do you feel the need to do that?BrenBarn– BrenBarn2015-01-03 21:09:57 +00:00Commented Jan 3, 2015 at 21:09
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just asking if it's possiblemagic-sudo– magic-sudo2015-01-03 21:10:24 +00:00Commented Jan 3, 2015 at 21:10
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Dear @BrenBarn I was asking if is possible to use if statements in lambda.magic-sudo– magic-sudo2015-01-03 21:21:58 +00:00Commented Jan 3, 2015 at 21:21
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@gml: In that case, you have your answer below. It is not possible to use any statements in a lambda.BrenBarn– BrenBarn2015-01-03 21:26:56 +00:00Commented Jan 3, 2015 at 21:26
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3 Answers
No, or at least not without assigning the function to a variable and then using that name to call it. But you still cannot use any statements in the function.
In any case, don't do that. A lambda function is exactly like a normal def function in Python besides the restriction that it cannot contain statements.
The only reason to use a lambda in Python is to avoid defining an named function if you just need a simple callable returning some value.
4 Comments
Kasravnd
what about
>>> fa= lambda x :1 if x <= 1 else x*fa(x-1) ?
ThiefMaster
Updated my answer to mention this case.
Kasravnd
@iCodez ohum , yep , i think so !
Yes, it is possible for this specific case.
>>> factorial = lambda x: 1 if x < 1 else x * factorial(x - 1)
>>> factorial(5)
120
I wouldn't recommend it though. A standard function definition seems far more readable to me.
Comments
>>> l = lambda i: 1 if i<=1 else i * l(i-1)
>>> l(5)
120
>>> 5*4*3*2*1
120
