remove the specific character in the string using javascript

Question

I have one string

 var tStr="[[[{"Name":"A","No":"8000444284"}],{"Name":"B","No":"8485990983"}],{"Name":"C","No":"0000000000"}]";

In this string i try to remove all [ and ]

My Code is:

function trim(str, characters) 
{
  var c_array = characters.split('');
  var result  = '';
  for (var i=0; i < characters.length; i++)
    result += '\\' + c_array[i];
  return str.replace(new RegExp('^[' + result + ']+|['+ result +']+$', 'g'), '');
}

And this Function Use as

trim(str,'[ ]');

In Calling var tStr="[[[{"Name":"A","No":"8000444284"}],{"Name":"B","No":"8485990983"}],{"Name":"C","No":"0000000000"}]";

thats not working please any one help me...:)

What is the problem with replace?

thefourtheye
– thefourtheye

2015-01-02 06:36:59 +00:00
Commented Jan 2, 2015 at 6:36 — thefourtheye
– thefourtheye, Commented Jan 2, 2015 at 6:36
you can use .replace() method str.replace('[','');

Innovation
– Innovation

2015-01-02 06:37:34 +00:00
Commented Jan 2, 2015 at 6:37 — Innovation
– Innovation, Commented Jan 2, 2015 at 6:37

vks · Accepted Answer · 2015-01-02 06:37:03Z

3

\[|\]

Try this.Replace by empty string.See demo.

https://www.regex101.com/r/fG5pZ8/4

var re = /\[|\]/g;
var str = '[[[{"Name":"A","No":"8000444284"}],{"Name":"B","No":"8485990983"}],{"Name":"C","No":"0000000000"}]';
var subst = '';

var result = str.replace(re, subst);

answered Jan 2, 2015 at 6:37

vks

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4 Comments

virbhadrasinh Gohil Over a year ago

Error Comes : Uncaught TypeError: undefined is not a function at the replace() function line

virbhadrasinh Gohil Over a year ago

the actual purpose is i have dictionary and that i convert into string than after convert into the dictionary then push one array and than using JSON storing into local-storage.

vks Over a year ago

@virbhadrasinhGohil should work.Check d demo.the code is working .There is problem somewhere else in ur code

virbhadrasinh Gohil Over a year ago

ya ya you are right, your answer is perfect ,this string is into the dictionary without convert into string i'll do this,, thx

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