Detecting specific browser versions using jQuery

Question

I have this piece of code that successfully detects Mozilla Firefox:

function isFFold() {
  return (
    (navigator.userAgent.toLowerCase().indexOf("firefox") >= 0)
  );
}

How can I alter the code so that I can get specific version? I have looked everywhere but the only way I find is using the deprecated browser function.

am using firefox and this happens to work quickly testing in console: navigator.userAgent.toLowerCase().split('/').pop() returns "34.0" I wouldn't use this in production for all browsers without testing — charlietfl
– charlietfl, Commented Dec 21, 2014 at 20:06

maja · Accepted Answer · 2014-12-21 20:12:01Z

2

I always use this code to check the user agent and it's version:

navigator.sayWho= (function(){
    var ua= navigator.userAgent, tem,
    M= ua.match(/(opera|chrome|safari|firefox|msie|trident(?=\/))\/?\s*(\d+)/i) || [];
    if(/trident/i.test(M[1])){
        tem=  /\brv[ :]+(\d+)/g.exec(ua) || [];
        navigator.isIE = true;
        return 'IE '+(tem[1] || '');
    }
    navigator.isIE = false;
    if(M[1]=== 'Chrome'){
        tem= ua.match(/\bOPR\/(\d+)/)
        if(tem!= null) return 'Opera '+tem[1];
    }
    M= M[2]? [M[1], M[2]]: [navigator.appName, navigator.appVersion, '-?'];
    if((tem= ua.match(/version\/(\d+)/i))!= null) M.splice(1, 1, tem[1]);
    return M.join(' ');
})();

It will tell you the name and the version of any user agent. Unfortunately, I don't know the original source of this code anymore.

Note that this code also works without jQuery.

However, you should try to avoid such code and use feature detection instead.

answered Dec 21, 2014 at 20:12

maja

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2 Comments

scooterlord Over a year ago

thanks, I am already using feature detection, but want to eliminate support for specific versions of browsers and below. However this is very general, I am very specific concerning firefox only.

maja Over a year ago

@scooterlord I posted another answer which will only detect firefox's version.

Shiladitya · Accepted Answer · 2017-10-26 07:05:56Z

2

As you only want to know the version of Mozilla Firefox, you can also use this function:

function getFFversion(){
  var ua= navigator.userAgent, tem;
  var match = ua.match(/firefox\/?\s*(\d+)/i);    
  if(!match){     //not firefox
    return null;
  }
  if((tem= ua.match(/version\/(\d+)/i)) != null) {
    return parseInt(tem[1]);
  }
  return parseInt(match[1]);
}

It will return the version as an integer. If the browser is not Mozilla Firefox, it will return null.

Your test function can look as follows:

void isFFold(minVer){
  var version = getFFversion();
  return ( version!==null && version < minVer );
}

(It will return false for non-firefox browsers)

edited Oct 26, 2017 at 7:05

Shiladitya

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answered Dec 24, 2014 at 13:55

maja

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