How to run a remote bash script with arguments from local

Question

I'm new to shell scripting and having a little trouble.

I'm trying to execute a remote script from local machine. The script on local machine is passed four arguments, and it executes the following line:

ssh $STACK 'bash -l -c "./deploy_intermediate.sh $2 $3 $4"'

However, I cannot get $2, $3, and $4 to put out the passed arguments. Is there any way to be able to access them within single quotes? What is the best way of executing the above line.

I would really appreciate any help.

thanks.

muratgozel · Accepted Answer · 2019-11-04 12:03:11Z

6

The trick is:

ssh -i ~/.ssh/"$GIT_PRIVKEY" user@"$IP" "bash -s" < localpath/script.sh "$arg1" "$arg2"

edited Nov 4, 2019 at 12:03

answered Dec 30, 2018 at 12:18

muratgozel

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1 Comment

Rany Albeg Wein Over a year ago

"Double quote" every literal that contains spaces/metacharacters and every expansion: "$var", "$(command "$var")", "${array[@]}", "a & b". See mywiki.wooledge.org/Quotes, mywiki.wooledge.org/Arguments and wiki.bash-hackers.org/syntax/words .

Rubens · Accepted Answer · 2014-12-13 02:00:26Z

1

To pass the parameters you'd have to write:

ssh $STACK 'bash -l -c "./deploy_intermediate.sh '$2 $3 $4'"'

Thus you make way for the $i values to be expanded. Yet, I think you'd probably be able to get the same result by simply running:

ssh $STACK "./deploy_intermediate.sh $2 $3 $4"

answered Dec 13, 2014 at 2:00

Rubens

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2 Comments

rici Over a year ago

But it will have surprising results if any of those arguments have whitespace or shell metacharacters in them.

Rubens Over a year ago

@rici Then escaping each variable with double quotes should suffice. Something like: ssh ... "./command \"$1\" \"$2\" ...".

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