Run PHP script(to create file) using cmd

Question

I m trying to run php script using cmd

CMD Code

"C:\wamp\bin\php\php5.4.16\php.exe" -f "C:\wamp\www\file\test.php"

PHP Code

$fileLocation = getenv("DOCUMENT_ROOT") . "/file/myfile.txt";//OR $fileLocation = "myfile.txt"
$file = fopen($fileLocation,"w");
$content = "Your text here";
fwrite($file,$content);
fclose($file);

Here problem is file is not created. If I run this file in browser then file is generate. user is administrator .

I don't think getenv("DOCUMENT_ROOT") renders anything useful... Echo that value and check if the result is what you were hoping it to be. — RichardBernards
– RichardBernards, Commented Dec 8, 2014 at 7:54

Yash · Accepted Answer · 2014-12-08 08:06:31Z

1

To run php code try this command:

php -f yourfilename.php

if you are in different location than specify absolute path. This will only work when you set your environment variable properly.

answered Dec 8, 2014 at 8:06

Yash

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3 Comments

Yash Over a year ago

replace '/file/myfile.txt' to '\file\myfile.txt' than it will work. actually it can not able to find the path of file.

srinath madusanka Over a year ago

set environment variable and your cmd type php -q pathtophpfile/yourfile.php

Yash Over a year ago

I run this on my localhost and its working properly. Code was like $file = fopen('D:\xampp\htdocs\file\hello.txt','w'); i faced problem when i assign path to a php variable.

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