Asyncjs parallel, run in loop

Question

I have an array with url's

var urls = ['http://google.com', 'http://example.com', 'http://localhost:300'];

and a function that reads from url

function readUrl(url) {....}

i wan't to run the function for all available urls in the array. Is that possible with asyncjs? or any other suggestion.

Your question could be interpreted as meaning you just want to run some function for each element of an array, which is just urls.forEach(readUrl). Presumably you're interested in doing something more interesting, such as running them in sequence, or running them in parallel and waiting until all they finish, or...?? Also, what does readUrl do--does it return a promise, because otherwise, with no callback visible in your example, there will be no way to tell if it's done at all. — user663031
– user663031, Commented Jun 30, 2016 at 14:24
dear downvoters care to comment please., at least strange downvote for answer which was accepted.. — Oleksandr T.
– Oleksandr T., Commented Jun 30, 2016 at 15:00
@torazaburo as I understood you downvoted for my answer, could you descrie why you have done it? — Oleksandr T.
– Oleksandr T., Commented Jun 30, 2016 at 15:15

Oleksandr T. · Accepted Answer · 2016-06-30 14:58:18Z

1

Is that possible with asyncjs?

yes, it is possible., like this

1.

var async = require('async');
var urls  = ['http://google.com', 'http://amazon.com', 'http://bing.com'];

function readUrl(url, next) {
  // some code  
  next(null, result);
}

urls = urls.map(function(url) {
  return function (next) {
    readUrl(url, next);
  };
});

async.parallel(urls, function(err, res) {
  console.log(err, res);
})

2.

var async = require('async');
var urls = ['http://google.com', 'http://amazon.com', 'http://bing.com'];

function readUrl(url) {
  return true;
}

urls = urls.map(function(url) {
  return function (next) {
    var res = readUrl(url);

    if (res) {
      return next(null, res);
    }

    next('Error');
  };
});

async.parallel(urls, function(err, res) {
  console.log(err, res);
})

edited Jun 30, 2016 at 14:58

answered Nov 19, 2014 at 8:38

Oleksandr T.

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