jquery array push to php foreach

Question

I'm getting this error in php:

Invalid argument supplied for foreach()

I am tring to create an array in jquery for the input values

<input type="text" class="passenger">
<input type="text" class="passenger">
<input type="text" class="passenger">

Then the js is :

var passengers = new Array();

$('.passenger').each(function(){
    if($(this).val() == " "){
        passengers.push(JSON.stringify($(this).val()));
    }
});

Then after i post it to php, i am wanting it so i displays all the passengers

at the moment, this is not working. Why not

foreach($passengers as $pass){
    $each_passengers = json_decode($pass);
}

$passengers is not a array but a string. You are doing a .stringify which convert the json data to a string. — S.Visser
– S.Visser, Commented Nov 17, 2014 at 12:02
You can use passengers.push($(this).val()); and var data = JSON.stringify(passengers) before data sending and then something like $passengers = json_decode($data) in PHP. — Regent
– Regent, Commented Nov 17, 2014 at 12:04

MixedVeg · Accepted Answer · 2014-11-17 12:18:39Z

2

Actually you don't need to stringify each input. What you need to do first, is create a grouping name attribute in your form inputs:

<input type="text" name="input[]" class="passenger" value="test1" />
<input type="text" name="input[]" class="passenger" value="test2" />
<input type="text" name="input[]" class="passenger" value="test3" />

Then, in your $.post(). Just feed them as serialized using $(form).serialize():

$.post('myphp_process.php', $('#form_values').serialize(), function(response){

Then of course the PHP that will process it, just treat it as normal POST:

$inputs = $_POST['input']; // this will return an array of inputs and to access this you need a loop.

// for clarity print_r($_POST['input']);

Check this out. This should give you the basic idea.

edited Nov 17, 2014 at 12:18

MixedVeg

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answered Nov 17, 2014 at 12:11

Kevin

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