Python: How to upload files to a specific folder in Google Drive using folderId

Question

So I am in the process of trying to upload a file to a specific Google Drive folder that a user specifies. Below is the code I have tried. I get the folderID and I try to post a file to the folder however I get a 404 Not Found error.

def post_file(self, files_to_send, config = {}):
  if config:
    if type(config) is str:
      config = literal_eval(config)
    path_id = config.get('path')
  for file_to_send in files_to_send:
    filename = file_to_send.name.split('/')[-1]
    status = self.call.post('https://www.googleapis.com/upload/drive/v2/files?uploadType=media/' + str(path_id) + "/children")

Using the interface on the Drive API documentation, I am able to get data with the same folderID but I am not able to post (Even with the interface). Files_to_send is a list with all the files that I need to upload to the specific folder, and config contains the folder path.

I need help understanding what I am doing wrong. I have read the documentation and looked at other answer but I have not found a solution. When I don't specify the folder ID, a dummy file does get posted to my drive, but it doesn't upload the file I want, and it doesn't upload anything at all when I specifiy a folderID.

Essentially, I need help inserting a file that comes in to a specific folder in Google Drive.

Thanks!

Lukas · Accepted Answer · 2019-10-28 14:52:46Z

7

in v3 just update file_metadata :

file_metadata = {'name': 'exmample_file.pdf', "parents": ["ID_OF_THE_FOLDER"]}

answered Oct 28, 2019 at 14:52

Lukas

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Omri Segal · Accepted Answer · 2014-11-06 15:49:28Z

4

I believe you should send a metadata JSON including a parents filed. Something like:

{
    "parents" : [path_id]
}

You can try this API here: https://developers.google.com/drive/v2/reference/files/insert

answered Nov 6, 2014 at 15:49

Omri Segal

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8 Comments

AlvinJ Over a year ago

I tried using the API however I still get a '404 Not Found'. This is the response below: "code": 404, "message": "File not found: "

Omri Segal Over a year ago

What is the exact URL you're using?

AlvinJ Over a year ago

What do you mean exact URL? Do you mean the ID of the folder?

Omri Segal Over a year ago

You seem to be sending a POST request to 'googleapis.com/upload/drive/v2/files?uploadType=media' + str(path_id) + "/children" What exactly does the URL look like after this string is concatenated?

AlvinJ Over a year ago

googleapis.com/upload/drive/v2/files?uploadType=media/… That is an example of what the URL looks like going into the POST

|

Gavriel Cohen · Accepted Answer · 2017-11-05 12:04:40Z

3

Two steps are required to resolve this issue:

Get folder id:

folder_list = self.drive.ListFile({'q': "trashed=false"}).GetList()
    for folder in folder_list:
         print 'folder title: %s, id: %s' % (folder['title'], folder['id'])

After found the ID Of required folder, Use this func:

def upload_file_to_specific_folder(self, folder_id, file_name):
    file_metadata = {'title': file_name, "parents": [{"id": folder_id, "kind": "drive#childList"}]}
    folder = self.drive.CreateFile(file_metadata)
    folder.SetContentFile(file_name) #The contents of the file
    folder.Upload()

edited Nov 5, 2017 at 12:04

answered Oct 26, 2017 at 15:42

Gavriel Cohen

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Comments

Fethi Pounct · Accepted Answer · 2020-11-30 06:53:08Z

3

for a concret sample

...
from googleapiclient import discovery
from apiclient.http import MediaFileUpload
...
drive_service = discovery.build('drive', 'v3', credentials=creds)
...
def uploadFile(filename, filepath, mimetype, folderid):
    file_metadata = {'name': filename,
                     "parents": [folderid]
                     }
    media = MediaFileUpload(filepath,
                            mimetype=mimetype)
    file = drive_service.files().create(body=file_metadata,
                                        media_body=media,
                                        fields='id').execute()
    print('File ID: %s' % file.get('id'))
  
#sample to use it:
filename = 'cible.png'
filepath = 'path/to/your/cible.png'
mimetype = 'image/png'
folderid = 'your folder id' #ex:'1tQ63546ñlkmulSaZtz5yeU5YTSFMRRnJz'
uploadFile(filename, filepath, mimetype, folderid)

answered Nov 30, 2020 at 6:53

Fethi Pounct

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1 Comment

Mhadhbi issam Over a year ago

worked , very Good

Keysinnovation · Accepted Answer · 2017-05-03 18:57:43Z

1

The way I achieve to put the file in the specific folder was by passing below info in metadata.

Here <someFolderID> info can be retrieve as: 1. go to google drive 2. select the folder 3. observe the address bar it will have some value after https://drive.google.com/drive/folders/

{
"parents":[
"id": "<someFolderID>",
"kind": "drive#file"
]
}

edited May 3, 2017 at 18:57

answered May 3, 2017 at 18:20

Keysinnovation

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1 Comment

manas Over a year ago

"parents":[] should have a enclosing {} within. ie. "parents":[{...}].

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