I am trying to compare an input string but when ever i enter barack as an input, the compiler directly goes to the else condition ignoring the the if condition and giving me the output "Wrong answer"
def main():
First_name = raw_input(" enter the first name of President Obama : ") #input
if First_name == ['b', 'a', 'r','a', 'c', 'k'] :
print "Correct answer"
else :
print "Wrong answer"
Exit_key = input('Press any key to end')
Is there a reason you are doing it like that? Try:
if First_name == "Barack" :
if First_name.lower() == barack will be more pythonicraw_input is a string so to do what you want you would have to call list on the string:
if list(First_name) == ['b', 'a', 'r','a', 'c', 'k'])
It is easier to just do if First_name == "barack"
In [1]: inp = raw_input()
barack
In [2]: list(inp)
Out[2]: ['b', 'a', 'r', 'a', 'c', 'k']
In [3]: inp
Out[3]: 'barack'
using lambda and map. just if you want to learn basic concept
if map(lambda x:x,First_name.lower()) == ['b', 'a', 'r','a', 'c', 'k']: