I'm trying to decode my password through a script while it's being run but it seems like the script is being run with a literal and the password is not processed. Is there a better way of doing this?
#!/bin/bash
MYENC="Tk9UX1RIQVRfU1RVUElEX0xPTAo="
rdesktop -u FOO -d mgmt -p 'echo $(echo $MYENC) | base64 --decode' 192.0.0.0
I also tried to just pass in a variable but that failed as well.
Try this instead:
#!/bin/bash
MYENC="Tk9UX1RIQVRfU1RVUElEX0xPTAo="
rdesktop -u FOO -d mgmt -p $(echo $MYENC | base64 --decode) 192.0.0.0
Note that I wrapped the juicy stuff echo...base64... in $(...). This is called "command substitution" - basically you're telling bash that you want the code inside the $(...) to be executed before the rest of the line, with the result substituted in its place. More info here: http://www.tldp.org/LDP/abs/html/commandsub.html
$(…) in place of back quotes.Or this
#!/bin/bash
MYENC="Tk9UX1RIQVRfU1RVUElEX0xPTAo="
rdesktop -u FOO -d mgmt -p $(base64 --decode <<< "$MYENC") 192.0.0.0
