#include<stdio.h>
int main(){
char *q;
int i=0;
do{
*(q+i)=getchar();
i++;
}while(*(q+i)!=48);
int j=0;
for(;j<i;j++)
printf("%c",*(q+j));
}
I try to use in this way. I could compile. However ıt does not work . My aim is that I wanna acquire char array (unlimited or limit will be defined by the user) What should I do?
You should read a book on C.
You're just writing into random memory, causing undefined behavior.
You must allocate memory, you can't just write through a non-initialized pointer!
For instance, make it:
char buffer[1024], *q = buffer;
Then make sure you don't overstep inside the loop, of course.
Also, there's no point in writing the access as *(p + i), when p[i] means the exact same thing and is much easier to read.
Finally, remember that technically getchar() returns int, since it can return EOF which is not a character.
1st allocate memory for your pointer *q
include<stdio.h>
int main()
{
int a;
char b[100];
int i=0;
char *p=b;
while((a=getchar())!=EOF)
{
p[i++]=a;
}
p[i+1]='\0';
printf("%s",b);
}
Also you can try heap memory allocation
char *p=(char*)malloc(40);
qchar[]will do. Avoid dynamic memory when you can, it's slower and adds complexity. Bugs like complexity