I have an array that contain number and string, I want to remove all string from the array. Here is the array:
var numbOnly = [1, 3, "a", 7];
In this case, I want to remove a from numbOnly (result numbOnly = [1, 3, 7]).
Thanks.
2 Answers
You can just use this:
var numbOnly = [1, 3, "a", 7];
var newArr = numbOnly.filter(isFinite) // [1, 3, 7]
The above works really well if you don't have strings like "1" in the array. To overcome that, you can filter the array like this:
newArr = numbOnly.filter(function(x){
return typeof x == "number";
});
1 Comment
elclanrs
I'd to do
.filter(isFinite). Number will filter out zeros.You can use Array.prototype.filter function along with Object.prototype.toString like this
var array = [1, 3, 'a', 7];
var numbOnly = array.filter(function(currentItem) {
return Object.prototype.toString.call(currentItem).indexOf('Number')!==-1;
});
console.log(numbOnly);
# [ 1, 3, 7 ]
Alternatively, you can use typeof to check the type like this
return typeof currentItem === 'number';
The filter function will retain the current element in the resulting list only if the function passed to it returns true for the current item. In this case, we are checking if the type of the current item is number or not. So, filter will keep only the items whose type is number, in the result.
typeof"a", nota? Or isaa variable containing a string?