How to open file using its default program in python

Question

How do I open a file from python? Not using the open() function and read or write, I mean simulate a user double clicking on the file. So if I open file1.jpg I want it to open using the default image program.

Thanks

u should import os, and use some appropriate tool... like xdg-open... i.e. _____ os.system(dxg-open) — mlwn
– mlwn, Commented Sep 17, 2014 at 22:15

Hasan Ramezani · Accepted Answer · 2014-09-17 22:21:45Z

3

in linux you can use xdg-open like bellow:

from subprocess import call
call(['xdg-open','filename'])

answered Sep 17, 2014 at 22:21

Hasan Ramezani

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tdelaney · Accepted Answer · 2014-09-17 22:19:29Z

0

On windows, you get this behavior if you execute through the win32 shell. An easy way to do that is with the subprocess module:

import subprocess as subp
subp.call('file1.jpg', shell=True)

answered Sep 17, 2014 at 22:19

tdelaney

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