What is the prototype of a Function object in Javascript?

Question

I have just written this snippet of code.

 function Point(x,y){
        this.x = x;
        this.y = y;
    }
    var myPoint = new Point(4,5);
    console.log(myPoint.__proto__ === Point.prototype);
    console.log(Point.__proto__ === Function.prototype);
    console.log(Function.__proto__ === Object.prototype);

The first two expressions returns true but the 3rd expression returns false.I am not sure why it returns false, because as per the below image, it is supposed to return true. Inheritance

In the image you can notice Function.prototype's __ proto __ property point to Object.prototype.

Could anyone please clear my concepts?

hugomg · Accepted Answer · 2014-09-14 15:07:16Z

3

In the image you can notice Function.prototype's __ proto __ property point to Object.prototype.

But that is not what you tested! You tested Function.__proto__, which is actually equal to Function.prototype. Try this instead:

console.log(Function.prototype.__proto__ === Object.prototype);

answered Sep 14, 2014 at 15:07

hugomg

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3 Comments

LJᛃ Over a year ago

Maybe also note that the prototype of Function is actually the Empty function.

Deepak Kumar Padhy Over a year ago

You are correct. But what does this would return console.log(Function.__proto__); As function is also a predefined Object in jS.

hugomg Over a year ago

Ah, now I understand your question... Function is actually a predefined constructor function, not a predefined object. You can call new Function() similarly to how you can call new Point() and new Object()

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