let string = "hello hi"
var hello = ""
var hi = ""
I wan't to split my string so that the value of hello get "hello" and the value of hi get "hi"
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2 Answers
Try this:
var myString: String = "hello hi";
var myStringArr = myString.componentsSeparatedByString(" ")
Where myString is the name of your string, and myStringArr contains the components separated by the space.
Then you can get the components as:
var hello: String = myStringArr [0]
var hi: String = myStringArr [1]
Doc: componentsSeparatedByString
EDIT: For Swift 3, the above will be:
var myStringArr = myString.components(separatedBy: " ")
1 Comment
Dave
The above has changed in Swift 3, it is now: 'var arrayOfSeperatedParts = myOriginalString.components(separatedBy: "insertSeperatorHere")'
Here are split that receives regex as well. You can define extension for future usage:
Swift 4
extension String {
func split(regex pattern: String) -> [String] {
guard let re = try? NSRegularExpression(pattern: pattern, options: [])
else { return [] }
let nsString = self as NSString // needed for range compatibility
let stop = "<SomeStringThatYouDoNotExpectToOccurInSelf>"
let modifiedString = re.stringByReplacingMatches(
in: self,
options: [],
range: NSRange(location: 0, length: nsString.length),
withTemplate: stop)
return modifiedString.components(separatedBy: stop)
}
}
Examples:
let string1 = "hello world"
string1.split(regex: " ") // ["hello", "world"]
let string2 = "hello world"
string2.split(regex: "[ ]+") // ["hello", "world"]
Swift 2.2
extension String {
func split(regex pattern: String) -> [String] {
guard let re = try? NSRegularExpression(pattern: pattern, options: [])
else { return [] }
let nsString = self as NSString // needed for range compatibility
let stop = "<SomeStringThatYouDoNotExpectToOccurInSelf>"
let modifiedString = re.stringByReplacingMatchesInString(
self,
options: [],
range: NSRange(location: 0, length: nsString.length),
withTemplate: stop)
return modifiedString.componentsSeparatedByString(stop)
}
}
Swift 2.0
extension String {
// java, javascript, PHP use 'split' name, why not in Swift? :)
func split(regex: String) -> Array<String> {
do{
let regEx = try NSRegularExpression(pattern: regex, options: NSRegularExpressionOptions())
let stop = "<SomeStringThatYouDoNotExpectToOccurInSelf>"
let nsString = self as NSString // needed for range compatibility
let modifiedString = regEx.stringByReplacingMatchesInString (self, options: NSMatchingOptions(), range: NSRange(location: 0, length: nsString.length), withTemplate:stop)
return modifiedString.componentsSeparatedByString(stop)
} catch {
return []
}
}
}
Swift 1.1
extension String {
// java, javascript, PHP use 'split' name, why not in Swift? :)
func split(splitter: String) -> Array<String> {
let regEx = NSRegularExpression(pattern: splitter, options: NSRegularExpressionOptions(), error: nil)
let stop = "<SomeStringThatYouDoNotExpectToOccurInSelf>"
let modifiedString = regEx.stringByReplacingMatchesInString (self, options: NSMatchingOptions(),
range: NSMakeRange(0, countElements(self)),
withTemplate:stop)
return modifiedString.componentsSeparatedByString(stop)
}
}
Examples:
let string1 = "hello world"
string1.split(" ") // ["hello", "world"]
let string2 = "hello world"
string2.split("[ ]+") // ["hello", "world"]
4 Comments
Maxim Shoustin
@downvoter please describe
Tyler Liu
I didn't downvote. I know the disadvantage of the method: you don't known when the parameter is a plain string while when it is a regex pattern string. For example, what if I want to split a string by "\d+" (literal string, not regex)
masukomi
@TylerLong the method tells you it's a regexp. If you want to split by the literal "\d+" then you pass in a regex that describes that literal string. E.g.:
"\\\\d\\+"
ctietze
I'd suggest to rename the method to
func split(regex pattern: String) -> [String] so on the call-site it's string1.split(regex: " ") instead. ("pattern" because the regex is supposed to be NSRegularExpression) The existing CollectionType.split can take a single character, too, so it's hard to tell which one is called when the parameter is " " only.