Running a program in debug without hard coding DEBUG = True in Python

Question

I have a small "Hello World" Flask script that takes an output from a program, called rescuetime_api and puts it on a URL /blog. I wanted to run the script in Debug mode and hard-coded it into the top of my program but I was wondering if there is a way to pass this value through from my Bash shell. Thanks in advance for your help.

#Flask tutorial
import rescuetime_api as api
import os

from flask import Flask
app = Flask(__name__)

DEBUG = True

@app.route("/")
def hello():
    return "This is my homepage!"

@app.route("/blog")
def blog():
    result = api.download_rescuetime_json()[1][1]
    return "%s" % result

if __name__ == "__main__":
    if os.environ.get("FLASK_TUTORIAL_DEBUG"):
        DEBUG = True
    print "Running in debug:", DEBUG
    app.run(debug=DEBUG)

Saish · Accepted Answer · 2014-09-11 04:54:11Z

2

Your script already checks for the environment variable FLASK_TUTORIAL_DEBUG.

You could just set it in your shell, before executing the program:

export FLASK_TUTORIAL_DEBUG=1

and then run your program:

python myscript.py

And remember to unset the variable when you don't need it:

unset FLASK_TUTORIAL_DEBUG

edited Sep 11, 2014 at 4:54

answered Sep 11, 2014 at 4:42

Saish

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3 Comments

g.humpkins Over a year ago

Would I run python script.py and then export FLASK_TUTORIAL_DEBUG=1 or would I want to export the variable before running the script?

Saish Over a year ago

You would need to export it before running the python script.

abarnert Over a year ago

Or just FLASK_TUTORIAL_DEBUG=1 python myscript.py.

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