Javascript for loop find array of objects

Question

I have a list of objects in awards console.log(awards) looks like this..

[0]
[1]
count
next
previous
route
getRestangularUrl
getRequestedUrl
addRestangularMethod
clone
reqParams 
etc...

I want to loop each array of objects ignoring all the other stuff i.e just [0] and [1]. Now I can do this when I know how many objects there are however I could have 1 or 100s.

 for (var key in awards) {
    if (awards[0]){


         }
     if (awards[1]){


         }

 }

Is there a what in javascript to detect an array in the for look?

Are you asking how to tell if a variable contains a number?

Quentin
– Quentin

2014-09-08 10:23:10 +00:00
Commented Sep 8, 2014 at 10:23 — Quentin
– Quentin, Commented Sep 8, 2014 at 10:23

Madhur Ahuja · Accepted Answer · 2014-09-08 10:27:30Z

1

var index=0;

    for (var value in awards) 
    {

        if (value instanceof Array) {
            alert('value is Array!');
         } else {
              alert('Not an array');
          }

         index=index+1;

     }

answered Sep 8, 2014 at 10:27

Madhur Ahuja

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2 Comments

Prometheus Over a year ago

can I get the array number form this i.e. 0, or 1

shinobi Over a year ago

Use 'for(i=0;i<length; i++)' instead for optimized loop, rather than using both 'for in' and 'index' counter.

bmazurek · Accepted Answer · 2014-09-08 10:28:44Z

1

This should work !

var array = [1,2,3, [2,3], 4 , 5, [4,5]];

for (i in array){
  if (array[i] instanceof Array === false){
    console.log(array[i]);
  }
}

Have a nice develop day !

answered Sep 8, 2014 at 10:28

bmazurek

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Comments

shinobi · Accepted Answer · 2014-09-08 10:54:49Z

1

var i, length=awards.length;
for(i=0;i<length; i++){
    if(awards[i] instanceof Array){
        console.log("Array present at index " + i);
        console.log(awards[i]);
    }
}

Hope this is what you want. Let me know if this works for you.

answered Sep 8, 2014 at 10:54

shinobi

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