How to sort a list of an array depending by an object value

Question

we need to list an array sorting by an object value.

We have a list of films, sorted by alphabetical order, but we want to sort by genres.

here is the code listing in alphabetical order.

<?php
    foreach ($films as $film_id => $film) {

    echo "<ul>";
    echo '<li id="film_thumb">';
    echo '<a href="watch.php?id=' . $film_id . '" alt="ID">';
    echo '<img class="thumb_res" src=" ' . $film["thumb"] . '" alt="' . $film["name"] . '">' ;
    echo '</a>';
    echo '</li>';
    echo "</ul>";
} ?>

the function listing in alphabetical order is in the array file

sort($films, SORT_FLAG_CASE);

Here is the array

$films = array ();
    $films[1] = array(
        "name" => "21 Jump Street",
        "year" => "2012",
        "genre" => "Commedia",
        "path" => "media/01.mp4",
        "thumb"=> "media/thumb/01.png",
        );

now, we need to create a page that list these items ( film thumb ) in categories, so if i click on genre "Action", the page must to show only selected film genre, and not the others.

Many thanks, Andrea

Use array_filter() to filter array by some value

hindmost
– hindmost

2014-08-07 14:07:39 +00:00
Commented Aug 7, 2014 at 14:07 — hindmost
– hindmost, Commented Aug 7, 2014 at 14:07

Raphaël Malié · Accepted Answer · 2014-08-07 14:31:48Z

1

You can sort your array by genre with usort() :

usort($films, function($a, $b){
    return strcasecmp($a['genre'], $b['genre']);
});

If you want to get films from the selected genre, you can use array_filter() :

$films = array_filter($films, function($film){
    return $film['genre'] == 'Commedia';
});

answered Aug 7, 2014 at 14:31

Raphaël Malié

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