how to run shell script in background in unix

Question

how to run shell script in background in unix?

My script

#!/bin/sh
while [ true ]
do
    ps -fu $USER>>/home/axway/trace.log 2>&1 
    sleep 10
done

running above script (shellEx1.sh) in background by nohup command on promt

nohup ./shellEX1.sh &

having below isuue:

$ nohup ./shellEX1.sh &
[3] 19520
$ nohup: ignoring input and appending output to    `nohup.out'

What is the problem? The script should work. Nohup is just giving you a warning ... — Matteo
– Matteo, Commented Jul 17, 2014 at 7:22

ganeshragav · Accepted Answer · 2014-07-17 07:32:29Z

1

Its warning to say like the output of the script will be written in file 'nohup.out'. In order to remove this warning, you can try

nohup ./shellEX1.sh >/tmp/output.txt &

or

nohup ./shellEX1.sh >/dev/null &

answered Jul 17, 2014 at 7:32

ganeshragav

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Comments

Aiden880 · Accepted Answer · 2014-07-17 07:22:13Z

0

Just a thought, you could make it connect or create a screen instance at the start.

screen -S bashscript my bash script

answered Jul 17, 2014 at 7:22

Aiden880

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That's not at all what the OP is asking, though.