json decode with an array in php

Question

I am having a problem with getting data from json. I cant change the way it is saved in the database since it is generated by the framework and after that read for the fields generation. My json looks like this:

{"102":{"textinput":{"comment":"2"}},"104":"34"}

 OR

{"78":{"textinput":{"comment":"1"}},"82":"34"}

Comment value is my serialnumber that I net to get from this json. I tried with :

$json_sn = json_decode($customer_json_sn, true);
$snr = $json_sn['78']['textinput']['comment'];

But this is not the solution I need, since I never know the value of first numeric key, I cant rely on that. Any help would be appreciated.

Why not use array_keys to get the keys and maybe array_shift on the result to get the first one? — Sergiu Paraschiv
– Sergiu Paraschiv, Commented Jun 12, 2014 at 8:30

user1978142 · Accepted Answer · 2014-06-12 08:33:02Z

2

If this format is going to be always the same, you can use reset() function on this one. Consider this example:

$json_sn = json_decode($customer_json_sn, true);
$snr = reset($json_sn);
echo $snr['textinput']['comment'];

answered Jun 12, 2014 at 8:33

user1978142

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2 Comments

enigmaticus Over a year ago

what in case when it is not the same?

user1978142 Over a year ago

@enigmaticus assuming the json structure stays the same, reset() will just take that first element, so you dont hav the need to manually put the key since it will always change.

hansn · Accepted Answer · 2014-06-12 08:37:21Z

1

How about:

$snr_array = array()
foreach ($json_sn as $key)
    snr_array[] = $key['textinput']['comment'];

Edit: I just realized that you might just need/get one comment:

$key = key($json_sn);
$snr = $json_sn[$key]['textinput']['comment'];

edited Jun 12, 2014 at 8:37

answered Jun 12, 2014 at 8:32

hansn

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Comments

eltortuganegra · Accepted Answer · 2014-06-12 08:41:58Z

0

You can do:

<?php

$json = '{"78":{"textinput":{"comment":"1"}},"82":"34"}';

var_dump(json_decode($json, true));

$data = json_decode($json, true);

foreach( $data as $key => $value ) {

    # Check if exsit
    if (isset($value['textinput']['comment'])) {
        echo "Value: " . $value['textinput']['comment'];
    }
}

answered Jun 12, 2014 at 8:41

eltortuganegra

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