Loop structure, nested lists.

Question

This is a simple test function that is synonymous to my actual code. So I have an array of data structured like this,

a=[[1,2,3,4,5],[0,3,6,8,10],[[1,2,3,4],[1,2,3,4],[1,2,3,4],[1,2,3,4],[1,2,3,4]]]

I am trying to loop over it so that in each pass we get, the first element of the first list, first element in the second list, and then each element in the first list of the third list.

Like this.

for i,j in enumerate(a):
     print 'iterations',i
     print a[0][i]
     print a[1][i]
     print a[2][i][0]
     print a[2][i][1]
     print a[2][i][2]
     print a[2][i][3]

But for some reason I cant get passed i=2. Can anyone explain why and how I can rectify this. Thanks. There's no error it just ends at i=2.

yes it ends at 2 because u have list of three list at first level — sundar nataraj
– sundar nataraj, Commented Jun 2, 2014 at 13:02

m.wasowski · Accepted Answer · 2014-06-02 13:02:54Z

3

Look closely at structure of your data:

a = [
        [1,2,3,4,5],
        [0,3,6,8,10],
        [ 
            [1,2,3,4],
            [1,2,3,4],
            [1,2,3,4],
            [1,2,3,4],
            [1,2,3,4]
        ]
    ]

You clearly have only 3 elements in a, so 2 is the last index...

answered Jun 2, 2014 at 13:02

m.wasowski

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1 Comment

Fred Foo Over a year ago

Note that pprint.pprint can be used to spot this kind of error.

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