Default argument to Python attribute that is a function [duplicate]

Question

I was wondering if it is possible in Python to specify a default argument to a function attribute in Python (I know this is not the right terminology so here is an example):

def foo(x, y): 
    return x + y

my_foo = foo(y=50)

my_foo(25) #returns 75

Does this sound possible?

To have a default argument, use def foo(x=0, y=0): [...] directly — abrunet
– abrunet, Commented May 30, 2014 at 16:40

Community · Accepted Answer · 2017-05-23 12:20:55Z

2

from functools import partial
def foo(x, y): return x + y
my_foo = partial(foo, y=50)
my_foo(100)
Out[433]: 150

But you should know about this.

edited May 23, 2017 at 12:20

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answered May 30, 2014 at 16:40

newtover

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Comments

Ben · Accepted Answer · 2014-05-30 16:40:08Z

1

You'd do it in the function definition:

def foo(x, y=50):
    return x+y

if y isn't specified 50 is the default value:

print foo(25) # 25 is the value for x, y gets the default 50

answered May 30, 2014 at 16:40

Ben

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1 Comment

martineau Over a year ago

Your answer is only valid only because it doesn't matter which argument gets the default value for this particular sample function -- a fairly unique situation -- so isn't something generally applicable.

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