I am working on a javascript project and got an issue.
I have values like this: 1231+, 83749M, 123199B
I can get the numeric values/number only by doing this:
var theNumber = parseInt(1231+);
But how can I get the trailing characters like: +, M, B? I can't use substring because there can be more than one character. But characters will be always at the trail.
var orig = "1231+";
var theNumber = parseInt(orig);
var theChar = orig.replace(theNumber, "");
Replacing "1231" in "1231+" with "" leaves "+".
You could use an regular expression. Somhow like this:
var string = "1234+";
var regexp = /([0-9]+)(.*)/;
var result = regexp.exec(string);
The result will be:
[ '1231+',
'1231',
'+',
index: 0,
input: '1231+' ]
So result[1] will then be your number and result[2] your suffix.
use regular expressions:
Expression for you is : [\d]
Get all non numeric characters.
Code example
$(document).ready(function() {
var elem = '1234+';
alert(elem.replace(/\d/g, ''));
});
//Result +
If all you're concerned about is trailing characters and not worried if there are alphabetic characters in the middle of the string then you could use this regex -
[^\d]*$
A handy tool for regex testing is http://regexpal.com/
Given that we have a pattern, we can now match that -
var foo = '1231+';
var trailers = foo.match(/[^\d]*$/);
console.log(trailers);
Try this code
var n1 = "234234M",
n2 = "6546D",
n3 = "4455+";
alert(n1.replace(parseInt(n1), ""));
alert(n2.replace(parseInt(n2), ""));
alert(n3.replace(parseInt(n3), ""));
