var url = "journey?reference=123line=A&destination=China&operator=Belbo&departure=1043&vehicle=ARC"
How can I split the string above so that I get each parameter's value??
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@Diodeus I would like a solution that saves them all to an array and that I can use repeatedly on lots of URLsuser3605739– user36057392014-05-05 20:31:17 +00:00Commented May 5, 2014 at 20:31
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That is a secondary issue, once you've parsed the data and created the object.Diodeus - James MacFarlane– Diodeus - James MacFarlane2014-05-05 20:35:08 +00:00Commented May 5, 2014 at 20:35
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3 Answers
You could use the split function to extract the parameter pairs. First trim the stuff before and including the ?, then split the & and after that loop though that and split the =.
var url = "journey?reference=123line=A&destination=China&operator=Belbo&departure=1043&vehicle=ARC";
var queryparams = url.split('?')[1];
var params = queryparams.split('&');
var pair = null,
data = [];
params.forEach(function(d) {
pair = d.split('=');
data.push({key: pair[0], value: pair[1]});
});
See jsfiddle
Comments
Try this:
var myurl = "journey?reference=123&line=A&destination=China&operator=Belbo&departure=1043&vehicle=ARC";
var keyval = myurl.split('?')[1].split('&');
for(var x=0,y=keyval.length; x<y; x+=1)
console.log(keyval[x], keyval[x].split('=')[0], keyval[x].split('=')[1]);
Comments
to split line in JS u should use:
var location = location.href.split('&');
2 Comments
tomysshadow
Instead of location.href, it would be easier to use location.search which will only return the question mark and everything after it. Then just chop off the first character using a substring.
Nikita_Sp
@tomysshadow yeah! It's even better! Thanks!